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Mrac [35]
2 years ago
5

Find the product of (x + 5)(x − 5).

Mathematics
1 answer:
AfilCa [17]2 years ago
6 0

Answer:

x² - 30 + 5x

Step-by-step explanation:

(x + 5)(x − 5)

=x(x − 5)+5(x − 5)

=x² - 5 + 5x - 25

=x² - 30 + 5x

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P is a rectangle with a length 40 cm and width x cm
romanna [79]
We know that

the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm
the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18

the answer 
the ratio x:y is 25:18
4 0
3 years ago
Help me with this!!!
Evgesh-ka [11]

Answer:

Your answer is easy it is 30

please give brainliest

7 0
3 years ago
(GIVING BRAINLIEST!!!)
USPshnik [31]

Answer:

Scammed

Step-by-step explanation:scammed

6 0
3 years ago
Simplify 3 - (4x - 5) + 6.<br> A) 12x + 21 <br> B) 4x + 14 <br> C) 4x + 4 <br> D) -4x + 14
stepladder [879]

Answer:

D) -4x+14

Step-by-step explanation:

We are given with the expression

3 - (4x - 5) + 6

Here we are going to open the bracket at first step

as we have a negative sign in front of bracket the signs of the terms inside brackets will be reversed

3-4x+5+6

now we bring the like terms together

3+5+6 - 4x

Here 3, 5, 6 all are constant and hence like

14-4x

or

3 - (4x - 5) + 6= -4x+14

Hence our answer is -4x+14

6 0
3 years ago
The question is in the screenshot attached. Thank you!
Rzqust [24]

Answer:

Domain: -4 < x < 4

Zeros: (-2, 0), (0, 0) and (2, 0)

The function is positive if: 0 < x < 2

The function is negative if: -4 < x < 0 and 2 < x < 4

Step-by-step explanation:

Domain of the function are those x values where the function is defined, For this case, -4 < x < 4

Zeros of a function are those x values where y = 0, that is, the graph intersect x-axis. For this case, the points are: (-2, 0), (0, 0) and (2, 0)

The function is positive if the graph o the function is above x-axis. For this case, the function is positive at the interval (0, 2)

The function is negative if the graph o the function is below x-axis. For this case, the function is negative at the intervals (-4, 0) and (2, 4)

7 0
3 years ago
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