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andrew11 [14]
3 years ago
12

Please answer this question for brainliest!

Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Because they are similar all sides would have the same ratio.

Find the ratio of two known sides:


AD = 4

EH = 16

16/4 = 4


The larger figure is 4 times larger.

Now multiply AB by 4 to get EF:

EF = 3 x 4 = 12 cm

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Mutiplying mixed numbers
Soloha48 [4]
You would first turn it into an improper fraction, to do this you leave the denominator(bottom number) then times it by your variable and add the numerator(top number)

Ex:

1 3/4x1/3= 7/12
7 0
3 years ago
87.125 is it rational or irrational? Explain how.
PSYCHO15rus [73]

Answer:

87.125 is rational

Step-by-step explanation:

it is a rational number because it can be represented as a fraction

6 0
2 years ago
Read 2 more answers
How many times does 4 go into 30
Leto [7]

The answer is 7 times 4 goes into 30.

<u>Step-by-step explanation</u>:

  • To check how many times a number goes into a larger number, use division.
  • Divide 30 by 4.

⇒ 4\times7 = 28 and 30-28 = 2

⇒ The quotient is 7.

⇒ The remainder is 2.

So, the number 4 goes 7 times into 30.

6 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
I need help tried to solve it, but can't....
fiasKO [112]

Answer:

B

Step-by-step explanation:

I would say B because if only 30 people said water and there is 65 that said something then it would almost be half of what you started with

8 0
2 years ago
Read 2 more answers
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