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MakcuM [25]
3 years ago
14

What operation must be used on the exponents in order to simplify the expression? (x^3)^7

Mathematics
1 answer:
mylen [45]3 years ago
3 0

Answer: So the trick I was taught to use was PEMDAS which stands for Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. You solve the parenthesis first, followed by exponents if there are any. Multiplication and division are equal. So if there's multiplication and division in the problem, you solve the one closest to the left or start of the equation first. The same rules apply for addition and subtraction. They are both equal so you solve the first one first, even if the subtraction is before the addition.

Step-by-step explanation:

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A bag contains 3 red, 6 blue, 5 purple, and 2 orange marbles. One marble is selected at random. What is the probability that the
mamaluj [8]

Answer:

P(blue)=37.5\%

Step-by-step explanation:

-Probability is the likelihood of an event occurring.

-The total number of events is:

Total=3+6+5+2\\\\=16

-The total number of blue events is:

Blue=6

#Probability of a blue is thus calculated as:

P(Blue)=\frac{Blue}{Total}\\\\=\frac{6}{16}\\\\=0.375\\\\=37.5\%

Hence, the probability of choosing a blue marble at random is 37.5%

6 0
2 years ago
Read 2 more answers
A patio in the shape of a semicircle has a diameter of 21 ft.
nikklg [1K]
The answer is 173 ft²

The area of the patio (A) is half of the area of the circle (A1) with a diameter of 21 ft:
A = A1/2

The area of the circle with radius r is: 
A1 = π * r²
π = 3.14
We do not have the radius, but we know that it is a half of the diameter:
r = 21 ft / 2 = 10.5 ft

A1 = 3.14 * (10.5)² = 346.18 ft²

So, the area of the patio is:
A = A1/2
A = 346.18 ft² / 2
A = 173.09 ft² ≈ 173 ft²
3 0
2 years ago
Find the area of the figure shown. Round your answer to the hundredths place. Use 3.14 for pi.
Grace [21]
There is no figure.
5 0
2 years ago
What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1
7nadin3 [17]
Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0) 
</span>
Explanation:
Given function:
f(x) =  \frac{3x^2 + x - 4}{x-1}

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \  ~ x =  \frac{-4}{3} \\ Hence~zeros=(  \frac{-4}{3}, 0)

5 0
3 years ago
PLEASE HELPPP!!!! :(
Svetach [21]

Answer:

i think its c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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