Answer:
60 miles
Step-by-step explanation:
Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?
Statement 1. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own
Statement 2. If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds
Solution
A. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
Let Brian speed=b
Ashok speed=a
Brian's walking speed=2(a-b)
b=2(a-b)
Divide both sides by 2
b/2=a-b
Ashok catches up in (time)= distance /( relative rate
=30/(a-b)
=30/(b/2)
=30÷b/2
=30*2/b
=60/b.
By that time Brian will cover a distance of
distance=rate*time
=b*60/b
=2(a-b)*60/2(a-b)
=60 miles
(2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
5a=3(a+b)
5a=3a+3b
5a-3a=3b
2a=3b
Answer:
(e) The women on the Maryland field hockey team are not a random sample of all female college field
hockey players. Similarly, the women on the Maryland basketball team are not a random sample of all female
college basketball players. However, for the purposes of this question, suppose that these two groups can be
regarded as random samples of all female college field hockey players and all female college basketball
players, respectively. If these were random samples, would you think that female college basketball players
are typically taller than female college field hockey players? Explain your decision using answers to the
previous questions and/or additional reasoning.
From 145 pounds to 132 pounds
145 - 132 = 13
13 pounds
Check:-
132 + 13 = 145
Correct!
13 pounds
