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3 years ago

5

In ΔABC, side AB is 8 units long and side BC is 25 units long. What cannot be the length of the third side

1 answer:

Anastasy [175]3 years ago

7 0

Answer: 35

Step-by-step explanation: The third side can be between the smallest side (8 units) and the two sides combined (25 + 8 = 32)

The third side can be anywhere from 8 - 32

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Which of the following equations could be used to solve the given equation? 9x + 26 + 7x - 17 = 2x + (-3x) + 5x

gavmur [86]

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3 years ago

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The original retail of a leather chair is listed at $121.40 and is discounted by 60% in a summer sale. What is the discount and

olga2289 [7]

Answer:48.56

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3 years ago

aul bought 9 total shirts for a total of $72. Tee shirts cost $10 and long sleeve shirts cost $7. How many of each type of shirt

vodomira [7]

Set up a system of equations:

$\text{Total shirts bought}$

$x + y = 9$

$\text{Total cost}$

$10x + 7y = 72$

x represents how many tee shirts were bought, and y represents how many long sleeve shirts were bought.

For the first equation, subtract y from both sides to get x by itself:

$x = 9 - y$

We'll now use substitution. Since x is equal to a value, we can substitute this value for the other equation:

$10(9-y) + 7y = 72$

Distribute the 10 to both terms in parentheses:

$10 \times 9 = 90$

$10 \times -y = -10y$

$90 - 10y +7y = 72$

Combine like terms:

$-10y + 7y = -3y$

$90 - 3y = 72$

Subtract 90 from both sides:

$-3y = -18$

Divide both sides by -3 to get y by itself:

$y = 6$

6 long sleeve shirts were bought.

Now you have a value for y. Input this value into the first equation:

$x + 6 = 9$

Subtract both sides by 6 to get x by itself:

$x = 3$

3 tee shirts were bought.

The answer is B. 3 tee shirts and 6 long sleeve shirts.

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3 years ago

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Calculate the area of a regular octagon if the radius is 10 cm long.

charle [14.2K]

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Area is A≈282.8 cm

Step-by-step explanation:

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2 years ago

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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

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2 years ago