Answer:
Following are the code to this question:
#include <iostream>//defining header file
using namespace std;//use package
void squareNreverse(int arr[], int size)//defining a method squareNreverse
{
int i,t,j;//defining integer variable
for (i = 0; i < size; i++)//defining loop for calculate square of array
{
arr[i] = arr[i] * arr[i];//calculate square and store its value
}
i = 0;//assign value 0 in i variable
j = size - 1;// hold size value
while (i < j)//defining while loop for calculate reverse value
{
t = arr[i];// store array value in t variable
arr[i] = arr[j];//defining arr[i] to store in arr[j]
arr[j] = t;//assign a[j] in t
i++;//increment i value
j--;//decrease j value
}
cout << "Displaying the Reveersed Array after Squared :" << endl;//print message
for (i = 0; i < size; i++)//defining for loop
{
cout << arr[i] << "\t";//print array value
}
}
int main()//defining main method
{
int size = 5;//defining size variable that hold value 5
int arr[size];//defining arr as an integer array
cout << "Enter elements :"; //print message
for (int i = 0; i < size; i++)//defining for loop for input value
{
cin >> arr[i];//input value
}
squareNreverse(arr, size);//call method squareNreverse
return 0;
}
Output:
Enter elements :2
3
4
5
6
Displaying the Reveersed Array after Squared :
36 25 16 9 4
Explanation:
In the given code a method, "squareNreverse" is defined that accepts an array and a size variable as a parameter, and inside the method, three integer variable "i,j, and t" is defined, in which i and j are used in the loop for calculating the square value and t is used for reverse the array value, and the print method is used for print reverse array value.
In the main method, an array "arr" and size is defined, which use for loop for input value from the user end, and at the last, we call the method "squareNreverse" bypassing array and size value.
