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andrezito [222]
3 years ago
12

design a relational database in EER for bike helmets and their reviews. a bike helmet has a name and color attributes. a bike co

mpany has its name (primary key) and location attributes
Computers and Technology
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:something you gotta do on your own

Explanation:

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What is a space flight that doesn’t complete a full orbit referred to as?
Vikentia [17]

Answer:

A flight that does not reach space is still sometimes called suborbital, but is not a 'suborbital spaceflight'. Usually a rocket is used, but experimental sub-orbital spaceflight has also been achieved with a space gun.

Explanation:

3 0
3 years ago
NEED FIVE QUESTIONS ANSWERED!!! take your time~
DochEvi [55]
  1. A
  2. C
  3. C
  4. B
  5. A

I'M NOT 100% SURE i hope this helps you

4 0
3 years ago
How to install windows 11 on unsupported processor
alexgriva [62]

Answer: You can't, if you anyway bypass the system, your device will run on risk.

Suggestion: Use any Linux distro similar windows 11. Like - Ubuntu/ Linux Mint/ ElementaryOs.

(Suggestion is only for if you can't run windows 10 or the pre installed Operating System in your machine.)

4 0
3 years ago
Give an example of an embedded systems application.
Gala2k [10]

Answer:

A clock in the mobile phone

Explanation:

a clock is a computer in a mobile phone which is a computer,hence it's a computer in a computer

7 0
3 years ago
Write function modifyString(origString, charsToReplace, count) that takes as input a string origString, a string charsToReplace,
laila [671]

Answer:

The code of the above program is provided below. using Python

Explanation:

<u>Code in Python 3:- </u>

def modifyString(origString,charsToReplace,count):

# Make s1 as original string

s1=origString

# Make s2 as charsToReplace string in lowercase

s2=charsToReplace.lower()

# Make s3 as charsToReplace string in uppercase

s3=s2.upper()

# Initialize answer as an empty string

ans=''

# Iterate the string upto length times

for i in range(len(s1)):

# check for chars in the string and append to the answer

if (s1[i] in s2) or (s1[i] in s3):

ans=ans+count*s1[i]

else:

ans=ans+s1[i]

# return the final string

return ans

print(modifyString("Our cat is funny","aeiou",5))    

print(modifyString("Our cat is funny","zu",3))

8 0
3 years ago
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