Answer:
a) RFID tags
Explanation:
yeah they're super expensive but keep everything secure so nothing gets in it .
Answer:
1. The data will not be tallying up - there will great variations and deviance.
2. There will be not enough data points
Explanation:
The management style, though it uses one manager, is not devoid of problems in the system. For example, there will be great difficulty in the collection of accurate data to properly define the system. This presents a great misinformation on the outcome of the data process. This is likely to be caused by the first factor that is the data having a lot of discrepancies. The discrepancy causes the data to be meaningless in terms of the trends displayed. In addition, the lack of enough points posses a challenge to the data collection and processing procedure. The data base management system can be used to concentrate data on a central point of reference.
For the view of Exercise 4.18, explain why the database system would not allow a tuple to be inserted into the database through this view.
For reference
For the database of Figure 4.12, write a query to find the ID of each employee with no manager. Note that an employee may simply have no manager listed or may have a null manager. Write your query using an outer join and then write it again using no outer join at all.
OUTER JOIN
select e.ID from employee e left outer join manages m on e.ID = m.ID
where m.manager_id is null;
NO OUTER
select e.ID from employee e where e.ID not in (select m.ID from manages m) or e.ID in (select m.ID from manages m where m.manager_id is null);
Answer:
The program is as follows:
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int num1, num2, num3;
cin>>num1>>num2>>num3;
cout << fixed << setprecision(2);
cout<<(num1 + num2 + num3)/3<<" ";
cout<<num1 * num2 * num3<<" ";
return 0;
}
Explanation:
This declares three integer variables
int num1, num2, num3;
This gets input for the three integers
cin>>num1>>num2>>num3;
This is used to set the precision to 2
cout << fixed << setprecision(2);
This prints the average
cout<<(num1 + num2 + num3)/3<<" ";
This prints the product
cout<<num1 * num2 * num3<<" ";
