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PSYCHO15rus [73]
3 years ago
13

Consider two consecutive positive integers such that the square of the second integer added to 3 times the first is equal to 105

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

8 and 9

Step-by-step explanation:

If x is the smaller integer, and x + 1 is the larger integer, then:

(x + 1)² + 3x = 105

x² + 2x + 1 + 3x = 105

x² + 5x − 104 = 0

(x + 13) (x − 8) = 0

x = -13 or 8

Since x is positive, x = 8.  So the two integers are 8 and 9.

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The line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9

<h3>Parallel Equations</h3>

The given equation is:

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Compare y = 4x + 5 with the equation y = mx + c

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The equation parallel to y = 4x + 5 will also have a slope, m = 4

The point-slope form of the equation of a line is given as:

y - y₁ = m(x - x₁)

substitute m = 4, x₁ = -2 and y = 1 into the equation above

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Therefore the line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9

Learn more on equation of a line here: brainly.com/question/13763238

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