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2 years ago

How do you solve this math problem of ratio?

Mathematics

1 answer:

Alex17521 [72]2 years ago

8 0

I don't know, this is tricky

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Solve 15n > 12n + 18

gogolik [260]

15n > 12n + 18
3n > 18
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2 years ago

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Janice is standing 15m form the base of a building. From the point where she is standing, the angle of elevation of the top of t

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Answer:

the building is 28m

Step-by-step explanation:

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2 years ago

Susanna has played the piano for s years. Patrick has played the piano for 4 more than twice the number of years that Susanna ha

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S=Years Susanna has played the piano
p=Years Patrick has played the piano

The expression for this question would be s(2)+4=p

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2 years ago

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Herman is traveling 125 miles from his house to the beach by car. Herman plans to stop for lunch when the ratio of the distance

aliya0001 [1]

Answer:

250 miles

Step-by-step explanation:

The given distance between the house and the beach is 125 miles.

Let $x$ miles be the distance between the house and the lunch stop.

So, at the time of the lunch stop, he already traveled $x$ miles, the remaining distance is the distance between the lunch stop and the beach.

Let $y$ miles be the remaining distance, so

$y=125-x.$

Give that the ratio of the distance he has traveled, $x$ , to the distance he still has to travel, $y$ , is $2:3$ ,i.e

$x:y=2:3$

$\Rightarrow \frac x y =\frac 2 3$

$\Rightarrow \frac {x}{125-x}=\frac 2 3$

$\Rightarrow 3\times x=2\times(125-x)$

$\Rightarrow 3\times x=2\times125-2\timesx$

$\Rightarrow 3 x=250-2x$

$\Rightarrow 3x-2x=250$

$\Rightarrow x=250$

Hence, the distance traveled by Herman when he stops for lunch is 250 miles.

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2 years ago

Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers

vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0

3 years ago