Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:
2.5 miles
Step-by-step explanation:
Mot enough information given.
The rule might be
-- add 6
or
-- double and add 8
or
-- square
or
-- multiply by -2 .
We need one more term to determine what the rule is for calculating the next term from the previous one.
The
It means that x value is between 2 to 7 ( more than 2, but less than 7)
In notation, 2 < x < 7 or (2,7).
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