Answer:
f. the sequence goes by the half of the previous number.
= 16, 8, 4, 2, 1, 1/2, 1/4, 1/8...
g. the sequence goes by adding the consecutive odd number added to the previous number.
first number= 3.
second number= 3+3
= 6
third number= 6+5
= 11
fourth number= 11+7
= 18
fifth number= 18+9
= 27
sixth number= 27+11
= 38
seventh number= 38+13
= 51, etc.
= 3, 6, 11, 18, 27, 38, 51...
Answer:
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Step-by-step explanation:
Considering the equation

Solving


As
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



![=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]](https://tex.z-dn.net/?f=%3D%5Cleft%28x%2B1%5Cright%29%5Cfrac%7Bx%5E4%2B8x%5E3%2B8x%5E2%2B8x%2B7%7D%7Bx%2B1%7D...%5BA%5D)
Solving


Putting
=
in equation [A]
So,
![\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]](https://tex.z-dn.net/?f=%5Cleft%28x%2B1%5Cright%29%5Cfrac%7Bx%5E4%2B8x%5E3%2B8x%5E2%2B8x%2B7%7D%7Bx%2B1%7D...%5BA%5D)

As

So,
Equation [A] becomes

So, the polynomial equation becomes







Keywords: polynomial equation
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I think he pays $702.
Basically,
650 • .08 (move the decimal over two to the left, that’s what you get) = 52. Then I did 650 + 52 and got $702.