Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Ill recomment on my thing right now with the answer let me just go read up on how to do this
Answer:
-2l -3
Step-by-step explanation:
5l -3+ (-7)l
5l -3 -7l
5l -7l -3
-2l -3
Answer:
1. TRUE
2. False
3. TRUE
4. False
5. TRUE
6. False
Step-by-step explanation:
1. 6859^(1/3) = 19 = ∛(19^3)
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2. 2197^(1/3) = 13 ≠ 9·2
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3. 8000^(1/3) = 20 = 10·2
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4. 9261^(1/3) = 21 ≠ 13
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5. 3375^(1/3) = 15 = 5·3
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6. 5832^(1/3) = 18 ≠ 3·7
