<span>(a) At the end of Month 0, about how many more insects were in Pod A than Pod B? Explain.
In Pod A, the point is higher than 50, it could be 60 to 70 insects. Pod B has 20 insects. So, Pod A has at least 40 insects more than Pod B.
(b) Find and compare the growth rates of each pod. Show your work.
Pod A: (0,60) ; (1,80) ; (2,100)
(80-60)/60 = 0.33
(100-80)/80 = 0.25
Pod B: (0,20) ; (1,44) ; (2,97)
(44-20)/20 = 1.2
(97-44)/44 = 1.2
Based on my computation, the rate of Pod A is lower than the rate of Pod B.
(c) When does the population in Pod B exceed the population in Pod A? Explain.
Pob B exceeds the population of Pod A at the END OF MONTH 4.
Pod A has a population of less than 200 while Pod B has a population of 469.</span>
Answer:
2a + 2b
Step-by-step explanation:
Since it's a rectangle, there are two sides with the length "a," and two sides with the length "b."
Let's say a = 4, and b = 8
2(4) + 2(8)
8 + 16 = 24
We can prove this is correct, by adding 4 + 4 + 8 + 8 together, since you're looking for the perimeter
I hope this helped :)
Answer:
70004
Step-by-step explanation:
1+1+4+4444+1928+63626 = 70004
To solve for a variable, isolate it! Get the variable alone on one side of the equation.
13) -15 = -4m + 5 ... -20 = -4m ... m = 5
14) 10 - 6v = -104 ... -6v = -114 ... v = 19
15) 8n + 7 = 31 ... 8n = 24 ... n = 3
16) -9x - 13 = -103 ... -9x = -93 ... x = 31/3
17) (n + 5) / -16 = -1 ... n + 5 = 16 ... n = 11
18) -10 = -10 + 7m ... 0 = 7m ... m = 0
19) -10 = -10(k - 9) ... 1 = k - 9 ... k = 10
20) (m / 9) - 1 = -2 ... m / 9 = -1 ... m = -9
21) 9 + 9n = 9 ... 9n = 0 ... n = 0
22) 7(9 + k) = 84 ... 9 + k = 12 ... k = 3
I cannot clearly read 23 and 24, but I hope you can see the principles I applied to produce these answers.