Answer:
in my opinion I think the answer is a because I don't know why
Step-by-step explanation:
Let
and 

We have 
Therefore

We have the equation of a line:
.
Put the coordinates of the point (8, 1) to the equation of a line:


<em>subtract 11 from both sides</em>

Answer: 
1. E
2. C
3. A
4. F
Those are the answers for those
In this question you need to isolate j. First you multiply 11 on both sides to make 3 + j not a fraction anymore.
3 + j = 22.
Then you isolate j by subtracting 3 on both sides since you must cancel the 3's out to isolate j. Then you get an answer of j = 19