Question

I need help can you help me???

Answer 1

A.

Answer:

~44.65 ft

Step-by-step explanation:

a = 25

b = 37

c = ?

c^2 = a^2 + b^2

So,

c = √a^2+b^2

c = √(25)^2+(37)^2

c = 44.6542271235 ft

the player is 44.65 ft from the hoop

B.

Answer:

50 ft

Step-by-step explanation:

a = 40

b = 30

c = ?

c = √(40)^2+(30^2

c = √1600+900

c = √2500

c = 50 ft

Answer 2

Answer:

1. about 7.87 feet away

2. About 8.37 yds

Step-by-step explanation:

1. a^2+b^2=c^2

so 25+37= C^2

= 62

Square root of 62 = 7.87400787401

(About 7.87 ft away)

2. 40+30 = C^2

Square root of 70 =  8.36660026534

About 8.37