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Alexus [3.1K]
3 years ago
12

What is the wavelength for radio waves with frequency 3 × 10^9?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

The answer is λ = 0.1 m

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Find a new function g(x) transformed from f(x)=-x-2 such that g(x) is perpendicular to f(x) .
sineoko [7]

The new function is g(x) =-1(1/-x) +2.

The transformation of function f(x) to function g(x) is given by g(x)=A f(Bx+ H)+K. where the constant A scales the function vertically. (A negative A reflects the function about the x-axis B scales the function horizontally. (A negative B reflects the function on the y-axis.) H shifts the function horizontally, and K shifts the function vertically.

Convert f(x) to g(x)

where the conversion is g(x)=f(x)+2.

A perpendicular line has negative reciprocal slopes, so for g(x) to be perpendicular to f(x), we need to get the negative reciprocal of -x, which is -1(1/-x)

So, f(x)=-x-2  ; m = -1

From the above information, we get g(x) as follows.

g(x) =-1(1/-x) +2

More problems related to finding new functions for a given function are below.

brainly.com/question/13825802?referrer=searchResults

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11 months ago
Ayuda por favor, me ayudan a resolverlo porfa.
frosja888 [35]
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8 0
2 years ago
What's the answer???
sertanlavr [38]
The answer is Letter "D"
4 0
3 years ago
In triangle PQR, PR = 23mm, QR = 39mm, and m<R = 163 degrees. Find the area of the triangle to the nearest tenth.
Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=\frac{1}{2} \times s_1\times s_2\times sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^{\circ},

Thus, the area of the triangle PQR,

A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}

A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}

5 0
3 years ago
Math question, I appreciate ANY help! :)
pav-90 [236]
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8 0
3 years ago
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