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Andrei [34K]
3 years ago
13

An object is moving at a speed of 230 feet per week. Express this speed in inches per

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

<em><u>I agree :) with the first person comment</u></em>

Dafna11 [192]3 years ago
5 0
You Americans are killing me with your inches per hamburgers and eagles per ar-15
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The area of a rectangular soccer field is 5000 yd^2. The length of the field is twice the length. Find the dimensions of the fie
harina [27]
You can divide the field into two squares of area 2500 yd^2. The side of each of those will be √2500 = 50 yd.

The dimensions of the field are 50 yd by 100 yd.
4 0
2 years ago
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1000x8129= WILL MAKR BRANLYEST
8_murik_8 [283]

Answer:

it is 8,129,000

Step-by-step explanation:

1000x8129 = 8,129,000

8 0
2 years ago
Write 9.3 million in scientific notation
svetoff [14.1K]

9.3 × 107 would be the scientific notation

3 0
2 years ago
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There was no actually pyramid for these questions it tells you the measurements in the problem though. please help me
Nimfa-mama [501]
V=448 in^3
l=8 in
w=12
h=?
V=l•w•h/3
448=8•12•h/3 multiply both sides by 3
3•448=96•h
1344=96•h
h=1344/96
h=14 in


V=l•w•h/3
h=4in
l=3in
w=2.5 in
V=?
V=4•3•2.5/3
V=30/3
V=10 in^3
3 0
3 years ago
Can anyone please help me in this
Alik [6]

These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.

We know that we can solve one variable equation easily. For example...

x+1=2

x=1 obviously

Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.

So what can we do? We have to make a two variable equation into a one variable equation.

There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.

x+y=2

2y-y=1

3)  

-3x-5y=-7 -----> -12x-20y=-28

-4x-3y=-2 ------> -12x-9y=-6

 -12x-20y=-28

-(-12x-9y=-6)

---------------------

-11y=-22

y=2

-3x-5(2)=-7

-3x=3

x=-1

4) 8x+4y=12 ---> 24x+12y=36

7x+3y=10 ---> 28x+12y=40

 28x+12y=40

-(24x+12y=36)

---------------------

4x=4

x=1

8(1)+4y=12

4y=4

y=1

5) 4x+3y=-7

-2x-5y=7 ----> -4x-10y=14

    4x+3y=-7

+(-4x-10y=14)

-------------------

-7y=7

y=-1

4x+3(-1)=-7

4x=-4

x=-1

6) 8x-3y=-9 ---> 32x-12y=-36

5x+4y=12 ---> 15x+12y=36

 32x-12y=-36

+(15x+12y=36)

--------------------

47x=0

x=0

8(0)-3y=-9

-3y=-9

y=3

7)-3x+5y=-2

2x-2y=1 ---> x-y=1/2 ----> x=y+1/2

-3(y+1/2)+5y=-2

-3y-1.5+5y=-2

2y=-0.5

y=0.25

2x-2(0.25)=1

2x=1.5

x=0.75

4 0
3 years ago
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