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Maru [420]
3 years ago
7

7

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

Answer:

Plan A equation:   y = 10x + 30

Plan B equation:  y = x + 80

Plan C equation: y = 5x + 50

Plan A costs the same as Plan C in 4 months

Plan A is the better option if you use 0 - 4 GBs of data each month

Plan B becomes the better deal when 8 months pass

Step-by-step explanation:

<u>When does Plan A cost the same as Plan C?</u>

Set the equations equal to each other (the cost) and solve for x (time in months)

10x + 30 = 5x + 50

5x = 20

x = 4 months

<u>Which plan is best if you only use 0-4 GBs of data a month?</u>

Test the maximum and minimum values to check which plan costs less

At 0 GBs of data used per month

Plan A:  y = 0 + $ 30 = $30 total

Plan B: y = 0 +$80 = $80 total

Plan C: y = 0 + $50 = $50 total

At 4 GBs of data used per month

Plan A: y = $ 40 + $ 30 = $ 70

Plan B: y = $ 4 + $ 80 = $ 84

Plan C: y = $ 20 + $ 50 = $ 70

Comparing the plans at maximum and minimum amount of GBs used, only one plan has the lowest cost overall. Even though Plan C is the same price at 4 GBs as Plan A, when you use 0 GBs you will end up paying more in Plan C than Plan A. Therefore, Plan A is the better option

<u>When does Plan B become the best deal?</u>

When you plot the different Plans on a graph, the slope intercept of x = 7.5 (rounded up to 8) yields the lowest cost for plan B

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Y is inversely proportional to the square root of x if y=3 when x=25 find y when x is 9
irga5000 [103]

Answer:

y=5

Step-by-step explanation:

\textsf{If }y \textsf{ is \underline{inversely proportional} to the square root of }x, \textsf{ then}:

y \propto\dfrac{1}{\sqrt{x}} \implies y=\dfrac{k}{\sqrt{x}}\quad \textsf{(where k is some constant)}

\textsf{When }x=25, y = 3:

\implies 3=\dfrac{k}{\sqrt{25}}

\implies 3=\dfrac{k}{5}

\implies k=15

Inputting the <u>found value of k</u> into the equation:

\implies y=\dfrac{15}{\sqrt{x}}

To find the value of y when x is 9, <u>substitute</u> x = 9 into the found equation:

\implies y=\dfrac{15}{\sqrt{9}}

\implies y=\dfrac{15}{3}

\implies y=5

8 0
2 years ago
A cube has surface area of 96 sq cm. What is the length of each edge of the cube?​
Sedbober [7]
96/6=16
Each side has area 16 sq cm.
Each edge length is sqrt(16)=4 cm
8 0
4 years ago
PLEASE HELP !!!!!!!!!!!!!!!!!
Gelneren [198K]

Answer:

Using the given information in the problem, the final evaluated answer is 31.

Step-by-step explanation:

3² + (8 - 2) · 4 - 6/3

First, subtract 2 from 8.

3² + 6 · 4 - 6/3

Next, evaluate the exponent in 3².

9 + 6 · 4 - 6/3

Now, multiply 6 by 4.

9 + 24 - 6/3

Next, divide 3 from 6.

9 + 24 - 2

Add together 9 and 24.

33 - 2

Lastly, subtract 2 from 33.

33 - 2 = 31

So, your final answer for this equation is 31.

6 0
3 years ago
Read 2 more answers
A rectangular goat pasture has dimensions represented by the expressions y – 4 and 4y^2-3y+5 .Find the area of the pasture.
Nataly_w [17]
Given that the goat pasture is rectangular with the dimensions given by:
Length=(y-4) and Width=(4y^2-3y+5)
Thus the area of the pasture will be given:
Area=length*width
Area=(4y^2-3y+5)(y-4)
Area=y(4y^2-3y+5)-4(4y^2-3y+5)
Area=4y^3-19y^2+17y-20
8 0
3 years ago
A crate contains cylindrical cans of soup for shipment. Each crate is a cube with side lengths of 14in. Each soup can is 6in tal
dalvyx [7]
Each cube has a side length of 14 in.
Each can of soup is 6 in tall and has a diameter of  3.5 in.

Refer to the figure shown below.

Top view:
For each side of the crate, number of cylinders that can fit in the crate is
14/3.5 = 4
Therefore 4² = 16 cylinders can be fitted in the crate (top view).

Side view:
The number of cylinders that can be stacked up in the crate is
14/6 = 2.333
Therefore only 2 rows are cylinders can be stacked up.

The total number of cylinders that will fit in a crate is 16*2 = 32.

Note:
Computing volumes for the crate and for a soup can will give wrong answers.
The volume of a soup can is V₁ = (3.14/4)*(3.5²)*6 = 57.6975 in³
The volume of a crate is V₂ = 14³ = 2744 in³
Therefore
V₂/V₁ = 47.55, that is 47  cans per crate.
The problem is that the geometry of the cans will make it impossible to fit 47 cans into the cube.

Answer: 32 soup can per crate.

6 0
3 years ago
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