All categories

3 years ago

What is the solution to the equation below?Round your answer to two decimal places.6+7*log2x=21

Mathematics

2 answers:

Kipish [7]3 years ago

5 0

Are you looking for x

Sloan [31]3 years ago

4 0

Answer:

Solution of 6+7 log 2x=21 is x = 4.26

Step-by-step explanation:

We need to find solution of 6+7 log 2x=21

Solving

6+7 log 2x=21

7 log 2x=21 - 6

7 log 2x=15

log 2x= 2.14

2x = 8.52

x = 4.26

Solution of 6+7 log 2x=21 is x = 4.26

You might be interested in

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago

Write the slope intercept form of the equation of the line through the given point

ozzi

Answer:

y = $-\frac{3}{4}$ x

Step-by-step explanation:

slope-intercept form: y = mx + b

Given: slope(m) = $-\frac{3}{4}$ , point (4, -3)

We already have the value of m, but we need to find the value of b. To do this, input the given values of the slope and the point into the equation:

-3 = $-\frac{3}{4}$ (4) + b

Solve for b:

-3 = $-\frac{3}{4}$ (4) + b

-3 = -3 + b

0 = b

The value of b is zero. We can now write the equation:

y = $-\frac{3}{4}$ x + 0

y = $-\frac{3}{4}$ x

The equation written in slope-intercept form is: y = $-\frac{3}{4}$ x

8 0

3 years ago

a guy walks into a store and steals a $100 bill from the register without the owners knowldge. He then buys $70 worth of goods u

Elanso [62]

He lost $30 bc
Guy stole $100
Guy gave back $70
Owner gives hue $30 !
If that makes any sense ‍♀️

8 0

3 years ago

A farmer is building a new silo. The circular silo is 27 meters tall and has a radius of 14 meters. What is the area of the base

Aleks [24]

Answer:

Step-by-step explanation:

The base of the silo is a circle

Rea of the base of the silo = πr²

r is the radius of the silo

Given

radius r = 14m

Area of the base of the silo = π(14)²

Area of the base of the silo = 3.14(196)

Area of the base of the silo = 615.44

<em>Hence the area of the base of the silo is 615.44m²</em>

3 0

3 years ago

please help me with this IXL i only have an hour like i said on my last question and please tell me how to get the answer so i c

damaskus [11]

It is y=2x-6. Anymore questions?

3 0

3 years ago

Read 2 more answers