Answer:
the answer is D. the center of a circle
8^2 is 64, and 6+4=10 which is even
Our basis is the given ratio of 1:44. The actual rocket is obviously larger than the model rocket. Thus, it means that for every 44 ft of the actual rocket, the scale of the model rocket would be 1 ft. Through ratio and proportion, the solution is as follows:
1/44 = x/168
x = 3.818 ft
<em>The height of the model rocket, is approximately 3.8 ft.</em>
Answer:
D is correct option
Step-by-step explanation:
The correct option is D.
The standard quadratic equation is ax²+bx+c=0
Where a and b are coefficients and c is constant.
It means that constant are on the L.H.S and there is 0 on the right hand side.
Therefore to make it a quadratic equation first of all you have to add 11 at both sides so that the R.H.S becomes 0.
The given equation is:
2x2-x+ 2 = -11
If we add 11 on both sides the equation will be:
2x2-x+ 2 +11= -11+11
2x^2-x+13=0
Thus the correct option is D
You can further solve it by applying quadratic formula....
I’m very excited, I get to see my brothers so that’s fun
