Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
Choice D). 8
Step-by-step explanation:
The value on n is simply the number of values or the size of the sample data. In our case, we have a total of 8 data values. The value of n will thus be 8
Answer:
Step-by-step explanation:
Area of sector is given as θ/360*πr²
Where,
θ = central angel of sector, m < DCE = 60°
r = radius = 4 feet
Area of sector = 
Area of the sector = 8/3π ft²
6hrs = 360 minutes
360/7.5 = 48 bottles required
500g = 0.5kg
48x0.5 = 24 kg
24x 5 = 120p
