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3 years ago

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2. The amount paid for different weights of oranges at a farmer’s market are shown below.

1 answer:

Marina CMI [18]3 years ago

4 0

Answer:

8 -------$ 12

Step-by-step explanation:

There are different weights of oranges at a farmer’s market given in the question. Two oranges that is three dollars. So one orange will be of one point five dollars. Then five will be equal to seven point five dollars. Much easier form of calculation that is eight equal to seven point five plus one point five that is added three times. This gives the final value of eight oranges that is twelve dollars.

8------12$

2 orange = 3$

So 1 = 1.5$

5 = 7.5$

8 = 7.5 + 1.5 + 1.5 + 1.5

8 oranges = 12$

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The area of the cylinder is a function of its height (h) and radius, ( $\mathbf{4\sqrt 3}$ )

The exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

The given parameters are:

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$\mathbf{r=4\sqrt 3}$

The surface area of a cylinder is calculated as:

$\mathbf{Area = 2\pi rh + 2\pi r^2}$

Substitute values for Area

$\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}$

Divide through by pi

$\mathbf{56\sqrt 6= 2 rh + 2r^2}$

Substitute value for r

$\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}$

Collect like terms

$\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}$

Make h the subject

$\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}$

$\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}$

Rationalize

$\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}$

$\mathbf{h = 7\sqrt 2- 4\sqrt 3}$

Hence, the exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

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