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2 years ago

6

2. The amount paid for different weights of oranges at a farmer’s market are shown below.

1 answer:

Marina CMI [18]2 years ago

4 0

Answer:

8 -------$ 12

Step-by-step explanation:

There are different weights of oranges at a farmer’s market given in the question. Two oranges that is three dollars. So one orange will be of one point five dollars. Then five will be equal to seven point five dollars. Much easier form of calculation that is eight equal to seven point five plus one point five that is added three times. This gives the final value of eight oranges that is twelve dollars.

8------12$

2 orange = 3$

So 1 = 1.5$

5 = 7.5$

8 = 7.5 + 1.5 + 1.5 + 1.5

8 oranges = 12$

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2 years ago

Find the value of x. Please help

inna [77]

I guess this is the answer
$67 \times 2 = 134$
then:
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2 years ago

6th grade math !!!!!!!!!!!!!!!

nydimaria [60]

Answer:

x=3

Step-by-step explanation:

Well if 4x>10, then x needs to be more than 2.5, (because 2.5*4=10) So the only answer left is x=3

7 0

2 years ago

Read 2 more answers

The scheduled arrival time for a daily flight from Boston to New York is 9:35 am. Historical data show that the arrival time fol

Lady_Fox [76]

Answer:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean is:

$M = \frac{a+b}{2}$

The standard deviation is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

Arrival time of 9:18 am and a late arrival time of 9:41 am.

9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.

Mean:

$M = \frac{a+b}{2} = \frac{0+23}{2} = 11.5$

Standard deviation:

$S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(23 - 0)^{2}}{12}} = 6.64$

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

8 0

2 years ago

Help! What is the average rate of change of f(x)=x^2+3x+6 over the interval -3 less-than-or-equal-to x less-than-or-equal-to 3?

Makovka662 [10]

Answer:

The average rate of change of the function over the interval is 5.

Step-by-step explanation:

Average rate of change of a function:

The average rate of change of a function f(x) over an interval [a,b] is given by:

$A = \frac{f(b)-f(a)}{b-a}$

Interval -3 less-than-or-equal-to x less-than-or-equal-to 3

This means that $a = -3, b = 3$

$f(x) = x^2 + 3x + 6$

So

$f(b) = f(3) = (3)^2 + 3(3) + 6 = 9 + 9 + 6 = 24$

$f(a) = f(-3) = (-3)^2 + 3(-3) + 6 = 9 - 9 + 6 = 6$

Average rate of change

$A = \frac{f(b)-f(a)}{b-a} = \frac{24+6}{3-(-3)} = \frac{30}{6} = 5$

The average rate of change of the function over the interval is 5.

8 0

3 years ago