If Ann is at 0, Ben will be four units away from her which could be 4 or -4 so since Carl will be 2 units away from Ben, he the only possible locations are 6, or -6
A small outlier could affect the whole data set because it could reduce the mean, or make the average of the whole data set smaller.
An example would be the data set could be 1, 8, 9, 10
To find the mean you would add everything together then divide it by the number of numbers you just added together. The mean of this set would be 28/4 which equals 7. Now, if the outlier were -8 instead of 1, then the mean would be much different.
The perimeter of a semicircle consists of two parts. (the curve and bottom) That curve is half the distance around the circle, since it's been split in half. The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π. Using 3.14 for π, 8π = 8×3.14 = 25.12. As for the flat part, that is the diameter (distance across) our circle. The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii) If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16. Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
The shaded region has an area of 12 while the whole thing is 50 mutiply both by 2 to get the area of the shaded region and the whole thing by 100 After that subtract 24 from 100 and you get a 76 percent chance that you will randomly select an area in that box that isn't shaded.
