Since p = x² - 7, you can substitute/plug in p for x² - 7
So:
(x² - 7)² - 4x² + 28 = 5
(p)² - 4x² + 28 = 5 You can factor out -4 from (-4x² + 28)
p² - 4(x² - 7) = 5 Plug in p
p² - 4p = 5 Subtract 5
p² - 4p - 5 = 0 Your answer is C
Answer:
Mean = $229.32
Median = $231.15
Mode = $268.4
Step-by-step explanation:
Mean = the average.
The average is the sum of variables divided by the number of variables.
x = each variable
N = number of variables = 11
Average = (Σx)/N = (236.09 + 204.43 + 253.82 + 268.4 + 231.15 + 205.7 + 262.18 + 162.77 + 268.4 + 224.45 + 205.17)/11
Mean = 2522.56/11 = $229.32
b) Median is the value that falls at the middle of the data set if all the variables are arranged in ascending or descending order.
So, to find the Median, we first arrange the variables in ascending order.
162.77
204.43
205.17
205.70
224.45
231.15
236.09
253.82
262.18
268.4
268.4
Since there are 11 variables, the Median is the number that falls at the middle of the distribution, that is, at the sixth position.
Median = $231.15
c) Mode is the number that appears the most in a distribution.
In this distribution, only 268.4 appears more than once.
Hence, the more is $268.4
The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
Answer:
538826 ml
Step-by-step explanation:
I need help on that to. We have a test tomorrow and I can't figure it out and I need help:(
