What is the probability that a point chosen inside the large rectangle is not in the shaded region?

Mathematics

1 answer:

Maurinko [17]2 years ago

5 0

The shaded region has an area of 12 while the whole thing is 50 mutiply both by 2 to get the area of the shaded region and the whole thing by 100 After that subtract 24 from 100 and you get a 76 percent chance that you will randomly select an area in that box that isn't shaded.

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28. Express 22.7 : 45.4 as a single decimal

maria [59]

Answer:

0.5

Step-by-step explanation:

22.7: 45.4 = 22.7/45.4

= 227/454

= 0.5

4 0

2 years ago

Read 2 more answers

Question 101 points)

maw [93]

Answer:

$\large\boxed{y=-\dfrac{2}{3}x+\dfrac{13}{3}}$

Step-by-step explanation:

$\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\===============================$

$\text{We have the point:}\\\\(5,\ 1)\ \text{and}\ (-4,\ 7).\ \text{Substitute:}\\\\m=\dfrac{7-1}{-4-5}=\dfrac{6}{-9}=-\dfrac{6:3}{9:3}=-\dfrac{2}{3}\\\\\text{We have the equation in form:}\\\\y=-\dfrac{2}{3}x+b\\\\\text{Put the coordinates of the point (5, 1) to the equation:}\\\\1=-\dfrac{2}{3}(5)+b\\\\1=-\dfrac{10}{3}+b\qquad\text{add}\ \dfrac{10}{3}\ \text{to the both sides}\\\\\dfrac{3}{3}+\dfrac{10}{3}=b\to b=\dfrac{13}{3}\\\\\text{Finally:}\\\\y=-\dfrac{2}{3}x+\dfrac{13}{3}$