V=Bh (with B being the area of the base).
h=V/B, or 456/24, or <u>19</u>.
let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96.
Y⁴ + 12y² + 36
Now factorize the expression
y⁴ + 6y² + 6y² + 36
= y²(y² + 6) + 6(y² + 6)
= (y² + 6) (y² + 6)
<span>Now 6 is not the perfect square and according to rule, binomial can not be factored as the difference of two perfect squares.
</span>so multiply both.
(y² + 6)² is the answer.
