We are going to solve for x=-2, y=2/3x+3, y=2/3(-2)+3, y=5/3. Therefore, x=-2 and y=5/3
2+2a 1x4a
------ ------
b b
LOL, idk if this is right, but it is how i think it should be solved
Answer:
vertex = (- 1, 3 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
= - 
y = 2x² + 4x + 5 ← is in standard form
with a = 2, b = 4, then
= -
= - 1
Substitute x = - 1 into the equation for corresponding value of y, that is
y = 2(- 1)² + 4(- 1) + 5 = 2 - 4 + 5 = 3
vertex = (- 1, 3 )
(16y6)3 - (10z2)3 I think is the right answer
Answer:
250
Step-by-step explanation:
Pretty much every time it asks for the abasloute value it just asks how much to get the zero on the number line. It will ALWAYS be positive. For example -5 will be 5 to get to zero on the numberline. Same thing with a positive 5.