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Zinaida [17]
3 years ago
7

The PE class has 12 boys and 8 girls. What is the maximum number of teams that the teacher can divide the class into so that eac

h team has an equal number of boys and girls, the greatest common factor of the numbers of girls and boys? Factors of 12: 1, 2, 3, 4, 6, 12 Factors of 8: 1, 2, 4, 8
Mathematics
2 answers:
boyakko [2]3 years ago
7 0

Answer:

that answer to this is 4

Step-by-step explanation:

both 12 and 8 have a common factor of 4 so that's the answer

hope this helps

Ugo [173]3 years ago
6 0

Answer:

B. 4

Step-by-step explanation:

The maximum number of teams the teacher can divide the class into is 4. I got it right on ED2020.

You might be interested in
⚠️6TH GRADE MATH PLEASE HELP I WILL MARK CROWN⚠️
zaharov [31]

Answer:

0.40d

d - 0.60d

Step-by-step explanation:

d - 0.60

This doesn't work because it wants 60<em><u>%</u></em> 0.60 without the percent is a decimal number, and is not 60% of d.

100% - 60% = 40%

0.40d works because it is multiplying 0.40 and d which is also 40%.

d - 0.60d works because it is multiplying 0.60 and d which is also 60% and then subtract it from d.

0.60d doesn't work because it want the discounted price not the discount.

1 - 0.60d doesn't work because we don't know that d = 1, so it is subtracting the discount from 1 not d.

4 0
3 years ago
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
Please help meeeeee with this
aleksandrvk [35]
Alright, let's do all of these (though this is a bit long).
1.
The constant is 1.8. All other values are coefficients to variables, which as the name implies will change.
2.
1 hour is 60 minutes, 1 minute is 60 seconds.
So, 4.2 *60 *60 = 15120 seconds.
3.
<span>−5x−4(x−6)=−3-5x-4(x-6)=-3
Let's move all x to one side, and all other numbers to another.
-5x-4(x-6)=-3-5x-4(x-6)=-3
x can be any value you want, if you actually solve this you'll only end up with -3 = -3, which is correct, of course.
Let me show you:
</span><span>−5x−4(x−6)=−3-5x-4(x-6)=-3
+5x +4(x-6)        +5x +4(x-6)
-3 = -3
The value of x is irrelevant, then. X can be any real number.
4.
I'm going to assume it was an error in printing with this? If not please correct me.
m=a+2b(or b2)
subtract 2b from each
a=m-2b
(This question seems kind of odd. We should probably address this in the comments.)
5.
</span><span>5(x−2)<−3x+6
Move all x to one side, numbers to other.
5x-10<-3x+6
+3x     +3x
    +10      +10
8x<16
/8
<span>x < 2
</span>6.
y-3=3(x-5)
alright, to find zeros set one variable to zero and solve
x first
-3=3x-15
+15    +15
3x=12
/3
x=4
x-int is (4,0)
now y
</span>y-3=3(0-5)
y-3=-15
+3     +3
y=-12
so y-int is (0,-12)
i've got to sleep now so i'll do the rest tomorrow. Sorry for the incomplete answer.

8 0
3 years ago
Pls pls pls help
Natasha_Volkova [10]

Answer:

Parallelograms I, II, and IV

Step-by-step:

Area of parallelograms:

I. A=3*5=15 units squared

II. A=5*3=15 units squared

III. A=4*4=16 units squared

IV. A=5*3=15 units squared

So, parallelograms I, II, and IV have the same area of 15 units squared.

5 0
3 years ago
Explain what can happen if you line up the digits incorrectly when you rewrite addition problems
Natali [406]
You will get the incorrect answer because lining up the digits when adding or subtracting is important but it isn’t needed for multiplying.
6 0
3 years ago
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