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GaryK [48]
3 years ago
15

NEED HELP///WILLREWARD///WILL MARK BRAINLEST

Mathematics
1 answer:
viktelen [127]3 years ago
7 0
Z(-1,5) to Z'(1.1) ....from here you can see x moves up 2 units and y moves down 4 units

so
A(1,3) ... A' (3, -1)
P(-2,4) ...P' (0,0)

answer is B. second choice

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Please solve! Simplify and write without parentheses!
Bogdan [553]
18y to the 20th power minus 90y to the fifth power
8 0
3 years ago
What would this problems answer be ?12y=2 1\4
mafiozo [28]

Answer:

Step-by-step explanation:12y ×4 =21

48y=21

Y=0.44

Mark brainlest if correct pls

5 0
3 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

7 0
4 years ago
Simplify the algebraic expression -2(x - 3) + 4(-2x + 8)
dangina [55]
The answer to this equation is :-10x+38 because
-2x(x-3)+4(-2x+8)
(-2x+6)+(-8x+32)
(-2x+6)(-8x+32)
-2x+6-8x+32
-10x+38
7 0
3 years ago
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