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3 years ago

What is -(2 a + 2 b) + (4 a +4 b

Mathematics

2 answers:

Masja [62]3 years ago

8 0

answer: 2a+3b

I really hope this helped

tia_tia [17]3 years ago

3 0

Answer:

2a+2b is the answer

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Plz hurry! answer asap!!

Lena [83]

Answer:

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Step-by-step explanation:rjfnu4fburbf

4 0

2 years ago

Read 2 more answers

The owner of a stereo store wants to advertise that he has many different sound systems in stock. The store carries 6 different

Orlov [11]

Answer: 540

Step-by-step explanation:

Given : The owner of a stereo store wants to advertise that he has many different sound systems in stock.

Number of different CD players =6

Number of different receivers= 10

Number of different speakers = 9

We are assuming that a sound system consists of one of each .

Then by Fundamental principle of counting , we have

The number of different sound systems can he advertise = (Number of different CD players)x (Number of different receivers) x(Number of different speakers)

= 6 x10 x 9 =540

Hence, the number of different sound systems can he advertise =540

6 0

2 years ago

In a bag of marbles ½ are red, ¼ are blue, ⅙ are green, and 1/12 are yellow. You pick a marble without looking The marble is mos

ohaa [14]

It has to be red since there are the most red marbles in the bag

6 0

2 years ago

Write the equation of the circle below to complete the square. Also determine the area of the circle.

diamong [38]

Answer: $(x-7)^2+(y+2)^2=11^2$ ; $A=121\pi$

Step-by-step explanation:

I have never done a problem like this, so this is my first time attempting it.

The standard form for the equation of a circle is:

$(x-a)^2+(y-b)^2=r^2$

Begin by grouping the 'x' terms and 'y' terms:

$(x^2-14x)+(y^2+4y-68)=0$

Complete the square for the second polynomial:

$(\frac{b}{2} )^2=(\frac{4}{2} )^2=4$

$(x^2-14x)+(y^2+4y+4-4-68)=0$

$(x^2-14x)+(y^2+4y+4)-4-68=0$

$(x^2-14x)+(y^2+4y+4)-72=0$

$(x^2-14x)+(y+2)^2-72=0$

Do the exact same process with the other polynomial:

$(x^2-14x-72)+(y+2)^2=0$

Complete the square:

$(\frac{14}{2} )^2=49$

$(x^2-14x+49-49-72)+(y+2)^2=0$

$(x^2-14x+49)-49-72+(y+2)^2=0$

$(x^2-14x+49)-121+(y+2)^2=0$

$(x-7)^2-121+(y+2)^2=0$

Bring the 121 to the other side to get:

$(x-7)^2+(y+2)^2=121$

$(x-7)^2+(y+2)^2=11^2$

The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

$A=\pi r^2=121\pi$