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arlik [135]
3 years ago
13

What is the midpoint of the segment shown below ?

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

C) (x,y) = (\frac{5}{2} , \frac{7}{2} ) is the mid point of AB.

Step-by-step explanation:

Let A and B be the two end points of the segment shown.

So, the coordinates of the segment AB are A(2,2) and B(3,5).

Let (x,y) be the mid point of AB.

By mid point Formula,

Mid point (x, y) = (\frac{x_{1} + x_{2}  }{2} ,\frac{y_{1} + y_{2}  }{2})

⇒(x, y) = (\frac{2 + 3 }{2} ,\frac{2 + 5  }{2})

So, x = 5/2, and y = 7/2

Hence, (x,y) = (\frac{5}{2} , \frac{7}{2} ) is the mid point of AB.

(c) is the correct option.

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<em />

You're looking for a solution of the form

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where

u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt

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Compute the Wronskian:

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\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}

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