The correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
<h3>What is interval notation?</h3>
It is defined as the representation of a set of values that satisfy a relation or a function. It can be represented as open brackets and close bracket the close the brackets means the value is at the close bracket also included, and open bracket means the value at the open bracket does not include.
We have:
Continuous set of all numbers between 5 and 6, including 5, but not including 6.
From the above statement we can represent the number in the interval notation:
The numbers are between 5 and 6.
(5, 6)
As it is mentioned that 5 is included and 6 is not included, then:
[5, 6)
Thus, the correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
Learn more about the interval notation here:
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Hello!
Since D is the midpoint and the two equations are and both sides of point D the equations equal each other
9x - 7 = 3x + 17
Now you solve it algebraically
Add 7 to both sides
9x = 3x + 24
Subtract 3x from both sides
6x = 24
Divide both sides by 6
x = 4
Now we put this into both equations and add them
9(4) - 7 = 29
3(4) + 17 = 29
29 + 29 = 58
The answer is 58 units
Hope this helps!
Formula:
A(t)=P(1+(r/n))^)nt)
A(4)=2500(1+(0.04/4))^(4*4)
A(4) = 2500(1.01)^16
A(4) = 2500*1.1726
<span>A(4) = $2931.45</span>
Answer:
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Step-by-step explanation:
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600,000 because the number after the five is five so if the number is 5 or higher you round it up
