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Gwar [14]
3 years ago
5

Given that, in a certain school, the following are true, what is the probability that a student is taking both math and computer

science?
1. The probability that a student is taking math is 23%.
2. The probability that a student is taking computer science is 45%.
3. The probability that a student is taking math or computer science is 58%.

A) 8%
B) 11%
C) 68%
D) 81%
Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0

The probability that a student is taking both math and computer science is option B) 11%.

<u>Step-by-step explanation:</u>

Given that,

The probability that a student is taking math alone = 23%.

The probability that a student is taking computer science alone = 45%.

The probability that a student is taking math or computer science = 58%.

<u>To find the probability that a student is taking both math and computer science :</u>

We use the formula P(A∪B) = P(A) + P(B) - P(A∩B)

Here,

P(math ∪ computer) = P(math) + P(computer) + P(math or computer)

⇒ 23% + 45% - 58%

⇒ 10%

Therefore, 10% is the probability that a student is taking both math and computer science.

We can choose option B) 11% as the correct answer since it is nearest to the 10%.

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Show 2 different solutions to the task.
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Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

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1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

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When n is negative even integer

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2.By mathematical induction

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Suppose it is true for n=k

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