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3 years ago

Logging out, have a great summer break y’all. See you in 2 months

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

4 0

Answer:

ok person! thx for the points!

Step-by-step explanation:

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Convert the rate of 24 in/sec to an equivalent rate measured in ft/sec

motikmotik

2 feet in a second 12 inches in a foot

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3 years ago

What is the measure of BAC

monitta

Answer:

were is graph?

Step-by-step explanation:

4 0

3 years ago

14. Solve: (a) 2y - 1/2 = -1/3 (b) 6 + 5 (a - 1) = 30

Strike441 [17]

A)2y - 1/2 = -1/3

2y=-1/3+1/2

FIND THE LCM TO MAKE THE FRACTIONS LIKE FRACTIONS

LCM OF 3 AND 2 IS 6

-1/3*2=-2/6

1/2*3=3/6

-2/6+3/6=1/6

2y=1/6

y=1/6 ÷ 2

TAKING THE RECIPROCAL,

RECIPROCAL OF 2 IS 1/2

y=1/6*1/2

y=1/12

B) 6 + 5 (a - 1) = 30

6+(5)*(a)+(5)*(−1)=30(Distribute)

6+5a+−5=30

(5a)+(6+−5)=30(Combine Like Terms)

5a+1=30

5a=30-1

5a=29

a=29/5

15.sum of three consecutive integers=48

let the numbers be x ,x+1,x+2

x+x+1+x+2==48

3x+3=48

3x=48-3

3x=45

x=45/3

x=15

x+1=15+1=16

x+2=15+2=17

the numbers are 15,16,17

7 0

3 years ago

Round 14.857 to the nearest tenth

Mila [183]

14.9. this is because 8 is in the tenth place, and the next number is five. for numbers greater than 4, you round up, for four or less, you stay the same.

8 0

3 years ago

Read 2 more answers

Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each

julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

$P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}$

$P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108$

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that $P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2)$ . And

$P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227$

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

6 0

3 years ago