20 point question pls help
1 answer:
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Answer:
Step-by-step explanation:
Given
y = 3x + 1
Required
Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1
First, the slope of the line has to be calculated;
Th slope of a line is the coefficient of x in its linear equation;
This implies that the slope of y = 3x + 1 is 3
Having calculated the slope of the first line;
The relationship between both lines are perpendicularity; this implies that
Where m_1 = 3 and m_2 is the slope of the secodnd line
becomes
Divide both sides by 3
The equation of the line can be calculated using the folloing formula
Where and
The equation becomes
Cross multiply
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