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Kipish [7]
3 years ago
6

There are 5 people in a raffle drawing. Three raffle winners each win gift cards. Each gift card is the same. How many ways are

there to choose the winners? Decide if the situation involves a permutation or a combination, and then find the number of ways to choose the winners
Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

  • 10

Explanation:

Call the wiiners of the gift cards W₁, W₂, and W₃.

Since each gift card is the same, any permutation of those three winners,  W₁, W₂, and W₃ are equivalent. This is what tells that the order of the winners does not matter and that<u><em> the situation involves a combination instead of a permutation</em></u>.

Then, you have to calculate the combination of 3 winners, selected from a group of 5 people; that is:

_nC_m=\frac{m!}{n!(m-n)!}\\ \\_3C_{5}=\frac{5!}{3!(5-3)!}=\frac{(5)(4)}{(2)(1)}=10

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Answer:

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3 years ago
-7d=56<br><img src="https://tex.z-dn.net/?f=%20-%207%20%3D%2056" id="TexFormula1" title=" - 7 = 56" alt=" - 7 = 56" align="absmi
PtichkaEL [24]
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Step-by-step explanation:

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