The group of seventh graders will have 5 groups of five: 5 is the greatest multiple of 25, or 5*5=25. Then for the sixth graders there will be 4 groups of 5: because 4&5 are the greatest factors of 20 and you want the most amount of kids per group, you would have 5 kids in each group. Hope this helps.
Answer:
yes I can
Step-by-step explanation:
Trinomial 2x² + 4x + 4.
It's of the form ax²+bx+c and it's discriminant is Δ=b² - 4.a.c
(in our case Δ = 4² - (4)(2)(4) → Δ = - 32
We know that: x' = -1 + i and x" = -1 - i
If Δ > 0 we have 2 rational solutions x' and x"
If Δ = 0 we have1 rational solution x' = x"
If Δ < 0 we have 2 complex solutions x' and x", that are conjugate
In our example we have Δ = - 16 then <0 so we have 2 complex solutions
That are x'= [-b+√Δ]/2.a and x" = [-b-√Δ]/2.a
x' =
Answer:
a = 0
Step-by-step explanation:
a + 5 = -5a + 5 subtract 5 from both sides
a + 5 - 5 = -5a + 5 - 5
a = -5a add 5a to both sides
a + 5a = -5a + 5a
6a = 0 divide both sides by 6
6a / 6 = 0 / 6
therefore,
a = 0
-2(3x - 9) + 5x = -10
-6x + 18 + 5x = -10
-6x + 5x = -10 - 18
-x = -28
x = 28 <===
