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3 years ago

MATH HELP PLEASE!!!!!!!

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

4 0

$f(x) = \dfrac{4x - 3}{7}$

$y = \dfrac{4x - 3}{7}$

$x = \dfrac{4y - 3}{7}$

$7x = 4y - 3$

$7x + 3 = 4y$

$4y = 7x + 3$

$y = \dfrac{7x + 3}{4}$

$f^{-1}(x) = \dfrac{7x + 3}{4}$

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3 years ago

Discussion Topic

dsp73

Answer:

See below

Step-by-step explanation:

Let's suppose you're getting a new phone plan. The phone plan charges a flat fee of $5 and costs $9 a month. How can we represent this relationship?

Since $5 is a flat fee, it doesn't change based on how many months you've had the plan because it always remains $5, so this is our y-intercept.

Because the plan costs $9 a month, this represents our rate of change, or slope, showing that every month you have the plan, you multiply by $9.

So, we can show this as y=9x+5 where x is the number of months of the phone plan and y is the cost of the phone plan given x amount of months

Now, what if you wanted to know how much the phone plan would cost after 4 months?

Simple enough, we can just substitute x=4 into our equation and get y=9(4)+5=36+5=41. So, getting the phone plan for 4 months costs $41.

Let's take this the other way around. What if we wanted to figure out how many months of the phone plan are covered by $50?

We would then substitute y=50 into our equation and solve for x:

y=9x+5

50=9x+5

45=9x

5=x

This would mean $50 would cover 5 months of the phone plan.

All in all, these are real-life examples of algebra.

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