A baseball has a 45 cm diameter. what is the volume of the contents of the ball

2 answers:

5 0

First you need to find the radius. To do that you need to divide the diameter by two;

45 / 2 = 22.5

Then you plug the radius in the formula for a sphere. Which is...

V = (4 / 3)πr^3
First you need to find the volume with out pi

V = (4/3) π (45)^3
V= π (4/3) (91,125)
Your answer with out pi is...
V= (68,343.75) π cm^3
And with pi is...
V = 214,708.22 cm^3

Pepsi [2]3 years ago

3 0

Answer:

47732.14 cm³

Step-by-step explanation:

To find the volume of the sphere with a diameter of 45 cm, we simply use the formula for calculating volume of a sphere, since a base ball is also spherical in shape.

Volume of a sphere = 4/3 πr³

But in the question, we were given diameter, so we can find our radius using the diameter given.

radius = diameter / 2

radius = 45 / 2

radius(r) =22.5 cm

The constant value of π is always 22/7 or 3.142 unless stated otherwise.

We can now go ahead and insert our values into the formula;

Volume of baseball = 4/3 πr³

=4/3 × 22/7 × (22.5)³

= 1002375 / 21

=47,732.14 cm³

Volume of the baseball = 47,732.14 cm³

You might be interested in

Determine the value of variables a, b, and c that make each equation true.

jeyben [28]

Corrected Question

Determine the values of a, b and c that make each equation true.

$(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}$

Answer:

a=-5,
b=28
c=-11

Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

$\dfrac{1}{p^m}=p^{-m} \\\\(a^m)^n=a^{m X n}\\\\$If p^m=p^n,$ then m=n$

Therefore :

Part 1

$(x^a)^6=\dfrac{1}{x^{30}}\\\\x^{a*6}=x^{-30}\\6a=-30\\$Divide both sides by 6\\a=-5$

Part 2

To solve for b

$(x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\$Since they have the same base\\b=28$

Part 3

To solve for c

$(x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\$Just as in part 2, the two sides of the equality have the same base, therefore:\\-2c=22\\Divide both sides by -2\\c=-11$