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3 years ago

Given: f(x) = x - 7 and h(x) = 2x + 3

Mathematics

2 answers:

Vinil7 [7]3 years ago

4 0

Answer:

h(f(x)) = 2x - 11

(the second answer is f(h(x)) = 2x - 4)

Step-by-step explanation:

h(x-7) = 2(x-7) + 3

h(x) = 2x -14 + 3

h(x) = 2x - 11

Andrei [34K]3 years ago

3 0

<u>Answer:</u>

The correct answer option is h(f(x)) = 2x - 11

<u>Step-by-step explanation:</u>

We are given two functions:

$f(x) = x-7$ and $h(x) = 2x+3$

and we supposed to find another function which is $h(f(x))$ .

To find $h(f(x))$ , we need to substitute the value of $f(x)$ in the other function i.e. $h(x)$ to get:

$h(f(x)) = h(x-7)$

$h(f(x))= 2(x-7)+3$

$h(f(x))=2x-14+3$

$h(f(x)) 2x-11$

Therefore, the correct answer is h(f(x)) = 2x - 11.

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The _______ are all the counting numbers.

Bingel [31]

It cannot be be Integers because Integers include negative numbers (which are not counting numbers)

It cannot be real numbers because like integers, it includes negative numbers but also includes decimals which are not counting numbers

It cannot be absolute values because absolute values is the range of how far away a number is from 0 which obviously isn't counting

That leaves natural numbers which are counted in sequence which fits the definition needed

Answer: D. Natural Numbers

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3 years ago

Read 2 more answers

The population of a certain species of insects increases exponentially according to the model, P(0) = 952e0.12t where P is the n

NeX [460]

Answer:

A) 952 insects are in the original colony

B) 10494 insects are in the colony after 20 weeks

C) 25 weeks

Explanations:

The model representing the population of the species of insects

$P(t)=952e^{0.12t}$

An exponential growth is of the form:

$P(t)=P_0e^{kt}$

where P₀ is the original population

t is the time taken in weeks

Comparing the two equations:

$P_0=\text{ 952}$

952 insects are in the original colony

B. The number of insects that will be in the colony after 20 weeks

Substituting t = 20 into the function given

$\begin{gathered} P=952e^{0.12(20)} \\ \text{P = }10494 \end{gathered}$

C) If the population, P = 20000

$\begin{gathered} 20000=952e^{0.12t} \\ e^{0.12t}=\text{ }\frac{20000}{952} \\ e^{0.12t}=21.008 \\ 0.12t\text{ = ln(21.008)} \\ 0.12t\text{ = }3.04 \\ t\text{ = }\frac{3.04}{0.12} \\ t\text{ = }25 \end{gathered}$

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1 year ago

Each grade level at Hooperville Schools has 298 students.

madreJ [45]

Answer:

(a) 3,874 students.

(b) 46,488 students.

Step-by-step explanation:

We have been given the each grade level at Hooperville Schools has 298 students.

(a) To find the number of students that attend Hooperville Schools, we will multiply the number of grades by 298.

$\text{Students that attend Hooperville Schools}=13\times 298$