Anya graphed the line (y-2)=3(x-1) on the coordinate grid.

Mathematics

2 answers:

gregori [183]2 years ago

5 0

Answer: The slope is 3

Lostsunrise [7]2 years ago

4 0

Answer:

The slope of the line would be 3

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Alexxx [7]

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Which relation represents a function?

trasher [3.6K]

Answer:

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A relation must have no repeating x-values for it to be a function.

Set C does not have any repeating x-values, so it is a function.

Sets A, B, and D have repeating x-values, so they are not functions.

A: (0, 0), (2, 3), (2, 5), (6, 6)

B: (3, 5), (8, 4), (10, 11), (10, 6)

D: (13, 2), (13, 3), (13, 4), (13, 5)

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PSYCHO15rus [73]

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$Let \: \: \theta = \sin^{ - 1} (\frac{4}{5}) \\ \\ \therefore \: \sin\theta = \frac{4}{5} \\ \\ \because \: { \cos}^{2} \theta =1 - { \sin}^{2} \theta \\ \\ \therefore \: { \cos}^{2} \theta = 1 - (\frac{4}{5} )^{2} \\ \\ = 1 - \frac{16}{25} \\ \\ = \frac{25 - 16}{25} \\ \\ = \frac{9}{25} \\ \\ \therefore \:{ \cos}\theta = \pm \: \frac{3}{5} \\ \\ \because \: \theta \: lie \: in \: the \: first \: quadrant \\ \\ \therefore \: { \cos}\theta = \: \frac{3}{5} \\ \\ \implies \theta = { \cos}^{ -1 } \: \frac{3}{5}\\\\\implies \theta = { \cos}^{ -1 } \: \frac{3}{5}= { \sin}^{ -1 } \: \frac{4}{5} \\ \\ \therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) \\ \\ = \cos( \ {cos}^{ - 1} \frac{3}{5} ) \\\\ = \frac{3}{5} \\ \\ \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1} \frac{4}{5} ) = \frac{3}{5}}}$

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