Solve the following system:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4
In the first equation, look to solve for x:
{1.8 x - 0.5 y = -6.4
{0.6 x + 2.1 y = 2.4
1.8 x - 0.5 y = (9 x)/5 - y/2 and -6.4 = -32/5:
{(9 x)/5 - y/2 = -32/5
Add y/2 to both sides:
{(9 x)/5 = 1/10 (5 y - 64)
{0.6 x + 2.1 y = 2.4
Multiply both sides by 5/9:
{x = 1/18 (5 y - 64)
{0.6 x + 2.1 y = 2.4
Substitute x = 1/18 (5 y - 64) into the second equation:
{x = 1/18 (5 y - 64)
{2.1 y + 0.0333333 (5 y - 64) = 2.4
2.1 y + 0.0333333 (5 y - 64) = 2.1 y + (0.166667 y - 2.13333) = 2.26667 y - 2.13333:
{x = 1/18 (5 y - 64)
2.26667 y - 2.13333 = 2.4
In the second equation, look to solve for y:
{x = 1/18 (5 y - 64)
{2.26667 y - 2.13333 = 2.4
2.26667 y - 2.13333 = (34 y)/15 - 32/15 and 2.4 = 12/5:
(34 y)/15 - 32/15 = 12/5
Add 32/15 to both sides:
{x = 1/18 (5 y - 64)
{(34 y)/15 = 68/15
Multiply both sides by 15/34:
{x = 1/18 (5 y - 64)
y = 2
Substitute y = 2 into the first equation:
Answer: {x = -3, y = 2
You could have 34,884 desserts.
The fundamental counting principle says that to find the total we do choices x choices x choices....
In this case, we have 969*12*3 = 34884.
Answer:
2,090,000
Step-by-step explanation:
Area = Area of Chile + Area of Bosnia
Area of Chile = 2*1000000
Area of Bosnia = 9*10000
Area = 2,000,000 + 90,000
Area = 2,090,000
Answer:
Option (B)
Step-by-step explanation:
Domain of function is defined by the set of x-values (input values) and Range of a function is a set of y-values (output values).
From the graph attached,
Domain of f(x) → Set of all real numbers
Range of f(x) → y-values > 0
Domain of 
→ Set of all real numbers
Range of → y < 2
Therefore, domain of both the functions is a set of all real numbers.
Option (B) is the correct option.
2.50f=15
f=6
Thats what I think it is, I'm sorry if I'm incorrect.
