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8_murik_8 [283]
3 years ago
12

Katy's measured the growth of a plant seedling. The seedling grew 1/3 inch by the end of the first week. The seedling grew 5/6 i

nch by the end of the second week. About how much did the seedling grow in the fist 2 weeks?
Mathematics
2 answers:
Vikki [24]3 years ago
8 0
In the given problem it is already given that the seedling grew by 1/3 inch in the first week and 5/6 inch in the second week. Then it would not be a problem to find the total length of growth of the seedling.
The length up to which the seedling grew in 2 weeks = (1/3) + (5/6)
                                                                                     = (2 + 5)/6
                                                                                     = 7/6 inch
So the seedling grew by 7/6 inches in two weeks. I hope that this answer is what you were looking for. You can solve such problems in the future by following the method that is applied for solving this problem.
ddd [48]3 years ago
5 0
1/3 + 5/6 = 2/6 + 5/6 = 7/6
It grew by 7/6 or 1 1/6 inches by the first 2 weeks.
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Step-by-step explanation:

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(3, -7) = (x1, y1)

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To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

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2 - (-7) = 2 + 7 = 9

7 - 3 = 4

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The slope is \frac{9}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

2=\frac{9}{4}(7)+b

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The y-intercept is -\frac{55}{4}.

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Answer:

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Answer:

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The z-score probability distribution for the normal distribution is given by;

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