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Scilla [17]
2 years ago
11

what is the maximum number of relative extrema contained in the graph of this function ? F(x) = 3x^4 - x^2 + 4x - 2

Mathematics
1 answer:
Mademuasel [1]2 years ago
7 0

The maximum number of relative extrema of the given polynomial is; 3

<h3>How to find the maxima of a Polynomial Function?</h3>

When trying to find the maximum number of relative extrema of a polynomial, we usually use the formula;

Maximum number of relative extrema contained in a polynomial = degree of this polynomial - 1.

We are given the Polynomial as;

f(x) = 3x⁴ - x² + 4x - 2

Now, the degree of the Polynomial would be 4. Thus;

Maximum number of relative extrema = 4 - 1

Maximum number of relative extrema = 3

Read more about Polynomial Maximum at; brainly.com/question/13710820

#SPJ1

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Answer:

1/4, 1/8, 1/5, *Actually there are a <em>lot</em> of possibilities.*

Step-by-step explanation:

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3 years ago
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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

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y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
What is the surface area of the cube shown?
Kryger [21]

Step-by-step explanation:

solve for surface area

A=6a^2

a=edge

3 0
3 years ago
Find the volume of the cone. Use 3.14 for n. Round to the nearest tenth.
enyata [817]

Answer:

1590.6cm {}^{3}

Step-by-step explanation:

volume \: of \: a \: cone \: v =  \frac{1}{3}\pi \: r {}^{2} h \\ radius =  \frac{diameter}{2}  =  \frac{15}{2}  = 7.5 \\ v =  \frac{1}{3}  \times 3.42 \times (7.5) {}^{2} \times 27 \\ v =  \frac{3.142 \times 7.5 \times 7.5 \times 27}{3}    \\ v =  \frac{4771.9125}{3}  = 1590.6375 \\ v = 1590.6cm {}^{3} (approximatly) \\ please \: rate \: and \: mark \: brainliest

7 0
2 years ago
All of the following are equivalent, except.
yulyashka [42]

Answer: B.

Step-by-step explanation: This is because you can't possibly have an exponent, there are no two of the same value being multiplied together.

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2 years ago
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