Answer:
62,832 kilometers
Step-by-step explanation:
The first thing you want to notice is that it's giving you two pieces of one part, if that makes sense. The radius of the earth, and then the distance from the surface of the earth to the orbit. What you want to do is find the circumference of the orbit in relation to the center of the earth. So, as a result, you're going to add those two values together. 6400 + 3600 equals 10,000. Now this is only the radius, but in order to find the circumference, we need the diameter. To find the diameter, you multiply the number by two. 10,000 x 2 is 20,000. Now you multiply this number by pi to find your final answer. This answer is 62,832 kilometers.
I may not be able to use the appropriate vocabulary. But, the ratio of holiday stamps to president stamps is of 8:5 we can reach this conclusion because a ratio is just a fraction, if we put 40 over 25 we then put it in simplest form to get 8/5, or a ratio of 8 holiday stamps to every 5 president stamps
Answer:
∡SYZ = 34.2°
∡XYZ = 68.4°
Step-by-step explanation:
∡SYZ = 34.2° this must be true because this angle is congruent to ∡XYS
∡XYZ = 68.4° this must be true because ∡XYZ = ∡WYS + ∡SYZ
Answer:
289.92
Step-by-step explanation:
Multiply the numbers together
The system is:
i) <span>2x – 3y – 2z = 4
ii) </span><span>x + 3y + 2z = –7
</span>iii) <span>–4x – 4y – 2z = 10
the last equation can be simplified, by dividing by -2,
thus we have:
</span>i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
iii) 2x +2y +z = -5
The procedure to solve the system is as follows:
first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:
i) 2x – 3y – 2z = 4
iii) 2x +2y +z = -5
2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.
Equalize:
3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9
similarly, using i and ii, eliminate x:
i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
multiply the second equation by 2:
i) 2x – 3y – 2z = 4
ii) 2x + 6y + 4z = –14
thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:
3y+2z+4=-6y-4z-14
9y+6z=-18
So we get 2 equations with variables y and z:
a) 5y+3z=-9
b) 9y+6z=-18
now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.
Let's use elimination method, multiply the equation a by -2:
a) -10y-6z=18
b) 9y+6z=-18
------------------------ add the equations:
-10y+9y-6z+6z=18-18
-y=0
y=0,
thus :
9y+6z=-18
0+6z=-18
z=-3
Finally to find x, use any of the equations i, ii or iii:
<span>2x – 3y – 2z = 4
</span>
<span>2x – 3*0 – 2(-3) = 4
2x+6=4
2x=-2
x=-1
Solution: (x, y, z) = (-1, 0, -3 )
Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:
check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
