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3 years ago

Please help me with this

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer:

AB = 2*sqrt(5) or

AB = 4.47

Step-by-step explanation:

AB is the hypotenuse of a right triangle A and B and the corner where 2 and 4 meet.

The length of AB is governed by the Pythagorean Theorem.

AB^2 = x^2 + y^2 Substitute 2 and 4 for x and y

AB^2 = 2^2 + 4^2 Expand the right side

AB^2 = 4 + 16 Add the right side

AB^2 = 20 Take the square root of both sides

sqrt(AB^2) = sqrt(20)

Factor 20 = 2*2 *5

Rule: when taking the square root of a number the pairs can take 1 member of the pair outside the root sign and throw the other one a way.

AB = 2 * sqrt(5) One of the roots has been thrown away.

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2 years ago

X^2-8x+16=5 what are the solutions?

svp [43]

Hey!

The first step to solving this equation would be to subtract 5 from both sides of the equation.

Original Equation :
$x^{2}$ - 8x + 16 = 5

New Equation {Added Subtract 5 to Both Sides} :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Now we solve our new equation.

Old Equation :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Solution {Old Equation Solved} :
$x^{2}$ - 8x + 11 = 0

The next step would be to solve with the quadratic formula.

Quadratic Equation ( 1 ) :
$x = \frac{-(-8) + \sqrt{(-8)^{2} -4 * 1 * 11 } }{2*1}$

Quadratic Equation ( 1 ) {Solved} :
4 + $\sqrt{5}$

Quadratic Equation ( 2 ) :
$x = \frac{-(-8) - \sqrt{(-8)^{2}-4 *1*11 } }{2*1}$

Quadratic Equation ( 2 ) {Solved} :
4 - $\sqrt{5}$

So, our final solutions for the equation $x^{2}$ - 8x + 16 = 5 are...

x = 4 + $\sqrt{5}$

and 

x = 4 - $\sqrt{5}$

Hope this helps!

- Lindsey Frazier ♥

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3 years ago

Calculate the missing terms in each proportion.

Solnce55 [7]

Answer:

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3 years ago

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ch4aika [34]

20
---- = 5
4

hope helped

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4 years ago