There are 2 way to solve this.
one using Pythagoras theorem and 2nd using trigonometry
so lets solve it by both
using Pythagoras theorem we know
base^2 + perpendicular^2 = hypotanes^2
6^2 + x^2 = 12^2
36 + x^2 = 144
x^2 = 144- 36 = 108
x = √(108) = √( 2×2×3×3×3)
= (2×3) √ (3) = 6 √3
so answer is option 2
bow lets use trigonometry
we know
sin theta = perpendicular / hypotanes
sin 60 = x /12
x = 12 × sin 60
we kNow sin 60 = √3/ 2
so
x = 12×√3 /2 = 6√3
It should be 2 but i’m not positive
Answer:
x= 4 y= 7 z= -6
Step-by-step explanation:
solve for one and you get them all
First, I got rid of the z by multiplying common factors (multiplied z by 2) and added equations 2 and 3 together after multiplying by 2
4x - 3y - 2z = 7
-10x+10y+2z= 18
-6x+7y= 25
Then multiplied z by -3 (to get rid of the z) with the original equation 3
3x - 2y + 3z = -20
15x-15y-3z= -27
18x-17y= -47
Next find common thing between the 2 equations we got and multiply it by that and combine (we can multiply first equation by 3 to get rid of the x and solve for y)
-18x+21y= 75
18x-17y= -47
y=7
Work backwards, substitute 7 into the above equation, you get x= 4 and then same for z to get z= -6
Do you have any answer choices?
65/100 = 13/20
(divide by 5 on both sides)
Hope this helped!
