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Bingel [31]
3 years ago
13

How does an earthquake of magnitude 7.9 compare in intensity with an earthquake of magnitude of 3.7 on the Richter​ scale? The l

arger​ earthquake's intensity was nothing times as great as the smaller​ earthquake's intensity. ​(Round to the nearest whole number as​ needed.)
Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
We are required to compare the magnitude for two earthquake intensity:
the larger intensity is 7.9
the smaller intensity is 3.7
thus the ratio of the intensity will be:
(larger intensity)/(smaller intensity)
=7.9/3.7
=2.135
~2 
Thus we conclude that:
The larger earthquake's intensity was 2 times as great as the smaller earthquake's intensity. 

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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
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The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

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Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

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so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

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Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

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<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

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on simplification is

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