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nekit [7.7K]
3 years ago
11

Could anyone find this?

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

s=\sqrt{32}\\ \\ \text{By the Pythagorean Theorem}\\ \\ x^2=s^2+s^2\\ \\ x^2=32+32\\ \\ x^2=64\\ \\ x=\sqrt{64}\\ \\ x=8

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Simplify 6/18<br> pls help thx
olchik [2.2K]

Answer:

1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1 - {6/7 + (1/10 - 3/8 - 3 }
LenaWriter [7]
677/280 that is the answer
5 0
2 years ago
What is the missing length???​
Neporo4naja [7]

28 + 53 = 81.

180 - 81 = 99.

Your missing length is 99 degrees.

( Just remember that all triangles add up to 180 degrees )

If you need more help just message me

6 0
3 years ago
Question 2 of 20 :
Dennis_Churaev [7]

Answer:

A

Step-by-step explanation:

(3a^4-2a^2+5a-10)-(2a^4+4a^2+5a-2)

a^4-6a^2-8

5 0
3 years ago
A n =−1+3(n−1) an=−1+3(n−1) what is the 55 term in the sequence
Sindrei [870]
ANSWER

a_{55}=161


EXPLANATION

The general term for the sequence is


a_n=-1+3(n-1)


To find the 55th term, we have to substitute
n = 55
in to the general term and simplify.



This implies that,

a_{55}=-1+3(55-1)



a_{55}=-1+3(54)




a_{55}=-1+162



a_{55}=161


Therefore the 55th term is 161.
8 0
3 years ago
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