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3 years ago

Could anyone find this?

Mathematics

1 answer:

lina2011 [118]3 years ago

8 0

Answer:

Step-by-step explanation:

Since the squares have areas of 32u^2. The side lengths are

$s=\sqrt{32}\\ \\ \text{By the Pythagorean Theorem}\\ \\ x^2=s^2+s^2\\ \\ x^2=32+32\\ \\ x^2=64\\ \\ x=\sqrt{64}\\ \\ x=8$

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What is 213,548 to the nearest hundreds

Inga [223]

Answer:

Step-by-step explanation:

5 is in the hundreds place.

The answer should be 213500

8 0

3 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

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2 years ago

Add the two expressions.<br> 69 + 1 and q + 11<br> Enter your answer in the box.<br> Please help!!

Pavlova-9 [17]

Answer:

l think the answer is 81q

3 0

3 years ago

Someone please help me with this question, I don’t know what to do.

Lelu [443]

Answer:

22.5

Step-by-step explanation:

What you need to do is calculate the volume of the Box. With the box being the volume of the piramid added to the prism surrounding the box with volume 15.

If you want to calculate it yourself stop reading here, because I will work it out now.

Volume box = a*b*c

Volume prism = 15

Volume pyramid = (b * c * a)/3

The prism has the volume of the box minus the pyramid so

abc - (abc)/3 = 15

abc - (1/3)abc = 15

(2/3)abc = 15

abc = 22.5

So 22.5 is the volume of the figure

8 0

3 years ago

A 15. 0 cm object is 12. 0 cm from a concave mirror that has a focal length of 4. 8 cm. Its image is 8. 0 cm in front of the mir

Pachacha [2.7K]

Answer:

-10

Step-by-step explanation:

right on edge 2022

6 0

2 years ago