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Leto [7]
3 years ago
12

Use the quadratic formula to solve x² + 8x + 9 = 0.

Mathematics
2 answers:
Sav [38]3 years ago
5 0
<span>C. x = −6.6 and x = −1.4</span>
Monica [59]3 years ago
4 0

Answer:

C. x = −6.6 and x = −1.4

Step-by-step explanation:

mark the other guy with the "brainly" XD

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PLEASE help. I will mark as brainliest
finlep [7]

Answer:

C 35

Step-by-step explanation:

Brainliest

4 0
3 years ago
Read 2 more answers
Which functions have graphs that are steeper than the graph of f(x)=−3x^2?
netineya [11]

Answer:

g(x)=−4x^2  and m(x)=4x^2

Step-by-step explanation:

A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number.  If this number is between 0 and 1, the graph will be stretched horizontally.  If this number is greater than 1, the graph will be shrunk horizontally.  If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.

The graphs that are horizontally shrunk are steeper than the others.  This is m(x)=4x^2  and g(x) = -4x^2.

8 0
3 years ago
Chuck must save a total of 180 for a new bike. So far he has saved 4/5 of the amount. How much money has chuck saved for the bik
4vir4ik [10]
He has saved $144 out of $180
6 0
3 years ago
Bessy has 9 times as much money as Bob, but when each earns $4, Bessy will have 5 times as much money as Bob. How much does each
jeyben [28]
Let x=bob’s original amount of money
Let 9x=Bessy’s original amount of money

9x+4=5(x+4)
9x+4=5x+20
4x=16
x=4

9(4)=36

Bob had $4 before earning $4 and Bessy had $36 before earning $4
6 0
3 years ago
The number of electrical outages in a city varies from day to day. Assume that the number of electrical outages ( x ) in the cit
forsale [732]

Answer:

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

Step-by-step explanation:

Given the probability distribution table below:

\left|\begin{array}{c|cccc}x&0&1&2&3\\P(x)&0.8&0.15&0.04&0.01\end{array}\right|

(a)Mean

Expected Value, \mu =\sum x_iP(x_i)

=(0*0.8)+(1*0.15)+(2*0.04)+(3*0.01)

=0+0.15+0.08+0.03

Mean=0.26

(b)Standard Deviation

(x-\mu)^2\\(0-0.26)^2=0.0676\\(1-0.26)^2=0.5476\\(2-0.26)^2=3.0276\\(3-0.26)^2=7.5076

Standard Deviation =\sqrt{\sum (x-\mu)^2P(x)}

=\sqrt{0.0676*0.8+0.5476*0.15+3.0276*0.04+7.5076*0.01}\\=\sqrt{0.3324}\\=0.5765

Therefore, the mean and the standard deviation for the number of electrical outages (respectively) are 0.26 and 0.5765 respectively.

3 0
3 years ago
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