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Ivenika [448]
3 years ago
15

Please help maybe anyone know how to calculate just a) ir b)?

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

A is 16 and B is -243 and my calculator is a smart calulator

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erik [133]

Answer:

<u>Exponential model</u>

y=Ae^{rt}

where:

  • y = value at "t" time
  • A = initial value
  • r = rate of growth/decay
  • t = time (in years)

<h3><u>Part (a)</u></h3>

Given:

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  • t = 0 years

Substituting given values into the formula and solving for A:

\begin{aligned}y & =Ae^{rt}\\\implies 100 & = Ae^{r \times 0}\\100 & = Ae^0\\100 & = A(1)\\A & = 100\end{aligned}

<h3><u>Part (b)</u></h3>

Given:

  • A = 100 g
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Substituting the given values into the equation and solving for r:

\begin{aligned}y& =Ae^{rt}\\\\\implies 50 & =100e^{30.17r}\\\\\dfrac{1}{2} & = e^{30.17r}\\\\ln \dfrac{1}{2} & = \ln e^{30.17r}\\\\\ln 1-\ln2 & =30.17r \ln e\\\\0-\ln 2 & =30.17r(1)\\\\-\ln 2 & =30.17r\\\\r & = \dfrac{-\ln 2}{30.17}\end{aligned}

Therefore, the final equation is:

y=100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}

<h3><u>Question 1</u></h3>

<u>Part (a)</u>

Q:   From 100g how much remains in 80 years?

\begin{aligned}t=80 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)80}\\& = 15.91389949 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:  How long will it take to have 10% remaining?

10% of 100 g = 10 g

\begin{aligned}y=10 \implies 10 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{10} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{10} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 10}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 100.2225706\: \sf years\end{aligned}

<h3><u>Question 2</u></h3>

<u>Part (a)</u>

Q:   How much remains after 50 years (time)?

<u></u>

\begin{aligned}t=50 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)50}\\& = 31.70373153 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:   How long to reach 20 g (amount remaining)?

<u></u>\begin{aligned}y=20 \implies 20 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{5} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{5} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 5}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 70.05257062\: \sf years\end{aligned}

3 0
2 years ago
|60|____ |-60| <br><br> = <br><br> &lt; <br><br> &gt;
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Since modulus function always gives positive output so both numbers will be equal
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It is a 2 out of three chance of getting a composite number because that means that it is not odd. There are 10 odd numbers between 1 and 30 (2,3,5,7,11,13,17,19,23,29) and that means that there is a 20 out of 30, or 2 out of 3 chance taht the number will be composite.
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3 years ago
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